Unless your education of math is

broad and sufficient, it's going to be hard to understand, remember much less do the more complex formulas that will be necessary later in your career much less in doing taxes or figuring out how many CFM's you need for a home air conditioner.

Just because you do VxA=W or A2 + B2 = C2 a lot doesn't mean that you have the rest of the formulas down that should be learned or at least understood how to do.

You might be able to figure out how to determine

spherical candlepower from lumens but what do you do with the figure unless trig,

etc are fully understood even if not used much?

DC

VOLTAGE DROP OF

CONDUCTOR (cable) OF L LENGTH

V =

voltage drop, I =

current
R = resistance of

conductor per 1000 feet

L = length of

conductor in feet

R for 18awg = 6.51, 16awg = 4.09, 14awg = 2.58

12awg = 1.62, 10awg = 1.02, 8awg = 0.64

V = I * L * (R / 1000) * 1.004

The

effect of

voltage on a lamp will cause a significant change in lamp performance. For any particular lamp, light output varies by a factor of 3.6 times and life varies inversely by a factor of 12 times any percentage variation in supply. For every 1% change in supply

voltage light output will rise by 3.6% and lamp life will be reduced by 12%. This applies to both DC and

AC current. Most standard

line voltage lamps are offered at 130v. Since most

line voltage power is applied at 120volts, the result is a slight under voltaging of the

filament. The

effect of this is substantially enhanced lifehours, protection from

voltage spikes and energy cost savings.

Voltage and Light Output: The

effect of

voltage on the light output of a lamp is ±1%

voltage over the rated amount stamped on the lamp, gives 3.1/2% more light or Lumens output but decreases the life by 73% and vise a versa.

Do not operate quartz Projection lamps at over 110% of their design

voltage as rupture might occur. GE Projection So what does this mean as to why a 115v

HPL 575w lamp is going to be much brighter than that of a 120v

HPL 575w lamp on a 117v service and what is going to be the difference given each at rated

voltage has 300hrs of life and 16,520 lumens in output? What if each is dimmed to 80% for 3/4 of it's life?

Which is the proper way (most accurate way) of determining

power requirements, A) figure out how many thousands of watts of watts is the total load on the

system, and divide by 1,000 than times that figure by 8.3, multiply that figure by 1.2 for

safety and divide that figure by 3 for the phases, or B) distribute the load, take total wattage of each

leg, divide by 120 to get the amperage, multiply by 1.2 for a

safety factor, and round up to the next size service available for the load?

A

Sling lifting 1,000 pounds is attached so to its load so it forms a 60/30/90° triangle between its two hanging points and the hook, what is the approximate load on each diagonal

leg of the

sling?

On a double-purchase

counterweight system, how many feet does the

batten travel for every 1' of

arbor travel, and how many pounds of

counterweight are required for every pound of load given a 13% resistance factor?

Which is the proper formula for deadhang tension? (Length of member in tension) = L, (Vertical Length) = V, (Weight) = W, (Horizontal Distance) = H & (Tension) = T

H2/V2 (W2) = T; H/V (W) = T; L/V (W) = T; D2/L (W) = T

With rigging, figuring out structures or getting into the higher electrical problems the math gets harder yet. Take the math in school it will help make it easier to work with the formulas and understand what's going on later.