Hi everyone!
I'm an LD that mainly uses LEDs for my rig and I'm trying to accommodate a projectionist at an upcoming show so they can bring something with enough fire power. This is when the question of how many lumens my stage is actually putting out came up. I understand that this is a "fluid" measurement so my best guess would be to go full white and intensity just to establish the top of my output threshold (of course during a show I may never reach that point). I've performed this exercise in the past with an incandescent rig but not surprising the world of LED specs is a bit of a rabbit hole.
Our stage has 5 fixture types that I rotate out for different shows that include beams, spots, b-eyes and pars; currently have either lumen or lux specs for all of them. My question I guess is with the Lux formula (Lux=lumen/ft2). I can "visualize" this on a surface or screen but how does it work for a crowd or camera...what would the ft2 part of formula be? If I was at FOH with the projectionist would it just be our area? For a camera is the square footage just that of the device, so extremely small? I'm sure I've severely overthought this but once I sat down and actually thought about it the head scratching began. Thanks!
I'm an LD that mainly uses LEDs for my rig and I'm trying to accommodate a projectionist at an upcoming show so they can bring something with enough fire power. This is when the question of how many lumens my stage is actually putting out came up. I understand that this is a "fluid" measurement so my best guess would be to go full white and intensity just to establish the top of my output threshold (of course during a show I may never reach that point). I've performed this exercise in the past with an incandescent rig but not surprising the world of LED specs is a bit of a rabbit hole.
Our stage has 5 fixture types that I rotate out for different shows that include beams, spots, b-eyes and pars; currently have either lumen or lux specs for all of them. My question I guess is with the Lux formula (Lux=lumen/ft2). I can "visualize" this on a surface or screen but how does it work for a crowd or camera...what would the ft2 part of formula be? If I was at FOH with the projectionist would it just be our area? For a camera is the square footage just that of the device, so extremely small? I'm sure I've severely overthought this but once I sat down and actually thought about it the head scratching began. Thanks!